Question 1138116
he sold the car for 3/5 of the cost price and lost 750.


that means that 2/5 of the cost price must have been equal to 750.


that means that the cost of the car had to be 5/2 * 750 = 1875.


the cost of the car was 1875.


he sold it at 3/5 of the cost which would be 3/5 * 1875 = 1125.


he lost 1875 - 1125 = 750.


solution looks good.


solution is that he sold the car for 1125.


to solve using algebra, do the following.


let x = the cost of the car.


he sold the car for 3/5 * x and lost 750.


therefore 3/5 * x + 750 = x.


this means that 3/5 times the cost plus 750 equals the cost of the car.


subtract 3/5 * x from both sides of that equation to get 750 = x - 3/5 * x


simplify to get 750 = 2/5 * x


multiply both sides of this equation by 5/2 to get 750 * 5/2 = 2/5 * x * 5/2


simplify to get 750 * 5/2 = x


solve for x to get x = 5/2 * 750 = 1875.


the cost of the car is 1875.


he sold it for 3/5 * 1875 = 1125.


he lost 1875 - 1125 = 750.