Question 103916
g(x)= 4x+2,  h(x)= x-2 over 4
-----------
g and h are inverse to one another:

g[h(x)] = g[(x-2)/4] = 4[(x-2)/4] + 2 = x-2+2 = x

h[g(x)] = h[4x+2] = [4x+2 - 2/4  = 4x/4 = x

===============
Cheers,
San H.