Question 1138067

if he sells the car for 750 and 750 was 3/5 of the cost, then the cost of the car would be 5/3 * 750 = 1250.


you would solve that as follows:


let x = the cost of the car.


3/5 * x = 750.


multiplhy both sides of this equation by 5/3 to get x = 5/3 * 750.


this makes x = 1250, which is the cost of the car.


if the cost of the car is 750 and he sells it for 3/5 of the cost, then he sells is for 3/5 * 750 = 450.


in that case, you would solve it as follows.


let x = the price he sold the car for.


than x = 3/5 * 750.


solve for x to get x = 450.