Question 1137935
z=(x-mean)/sd
>(93.24-93)/0.6=0.4
probability z>0.4=0.3446

for the sample, z>(xbar-mu)/sigma/sqrt(n)
this is 0.24*sqrt(44)/0.6, invert and multiply when dividing
z>2.65
probability is 0.0040

Far less likely 44 boards will deviate by the same amount compared to one.