Question 1137967
{{{lim((theta)->0)}}}{{{ (1 - cos^2(theta))/(theta)^2 }}}= 


Apply L'Hopital's Rule


{{{lim(theta->0)}}}{{{ (sin^2(2theta))/2(theta)}}} =


Apply L'Hopital's Rule


{{{lim(theta->0)}}}{{{ (cos^2(2theta)*2)/2}}} =


{{{lim(theta->0)}}} {{{(cos^2(2theta))}}} =


Plug in the value : {{{theta=0}}}


{{{lim(theta->0)}}}{{{ (cos^2(2*0))}}} =


{{{lim(theta->0)}}}{{{ (cos^2(0)) =1}}}