Question 1137960
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<pre>
Recall that  sinh(x) = {{{(e^x - e^(-x))/2}}}.


Therefore, equation


    2e^x*sinh(x) = 3


is the same a


    {{{2*e^x*((e^x - e^(-x))/2)}}} = 3,   or


    {{{e^(2x)-1}}} = 3


    {{{e^(2x)}}} = 3 + 1 = 4,


     2x = ln(4)

     2x = 2*ln(2)

      x = ln(2).        <U>ANSWER</U>
</pre>

Solved.