Question 1137952


A rectangular room is {{{5m}}} longer than it is wide, and its perimeter is 
{{{P=22m}}}.

Find the dimension of the room.

{{{L=W+5m}}}......eq.1

{{{P=2(L+W)}}}....substitute {{{L}}} from eq.1 and {{{P}}}

{{{22m=2(W+5m+W)}}}...............solve for {{{W}}}

{{{22m/2=W+5m+W}}}

{{{11m-5m=2W}}}

{{{6m=2W}}}

{{{W=6m/2}}}

{{{W=3m}}}


go to {{{L=W+5m}}}......eq.1, plug in {{{W}}}

{{{L=3m+5m}}}

{{{L=8m}}}


so,the dimension of the room are {{{ 8m}}} by {{{3m}}}