Question 1137919


{{{c=(5/9)(f-32)}}}

if {{{f=5}}} degrees farenheit

{{{c=(5/9)(5-32)}}}

{{{c=(5/9)(-27)}}}...simplify

{{{c=(5/cross(9)1)(-cross(27)3)}}}

{{{c=5(-3)}}}

{{{c= -15}}} temperature on the Celsius scale