Question 1137809
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One of the dice is <font color=blue>4</font>, so the other dice must show one of these values
{<font color=red>4, 5, 6</font>}
in order to have the sum be 8 or greater


<font color=blue>4</font>+<font color=red>4</font> = 8
<font color=blue>4</font>+<font color=red>5</font> = 9
<font color=blue>4</font>+<font color=red>6</font> = 10
You can see that the blue die is held fixed to be that given 4, while the red die is allowed to vary as long as the two dice values add to something 8 or larger.


There are 6 ways to roll a die, and 3 of which are outcomes we want {4,5,6}. So the probability of having the red die land on those three values is 3/6 = 1/2 assuming each face is equally likely to land on.


Therefore, the final answer is 1/2


Edit: I may have made an error, so the tutor @ikleyn is probably correct. My apologies if 1/2 isn't the answer.
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