Question 1137795

{{{8 - 6y =12}}}...eq.1
{{{12x - 9y = 18}}}....eq.2

start with eq.1

{{{8 - 6y =12}}}...eq.1...if you have no {{{x}}}, just solve for {{{y}}}

{{{8 - 12 =6y}}}

{{{ - 4 =6y}}}

{{{y= - 4/6}}}

{{{y= - 2/3}}}

substitute in eq.2


{{{12x - 9(-2/3) = 18}}}....eq.2

{{{12x - cross(9)3(-2/cross(3)) = 18}}}

{{{12x - 3(-2) = 18}}}

{{{12x + 6= 18}}}

{{{12x = 18-6}}}

{{{12x = 12}}}

{{{x = 1}}}