Question 1137676
set g(t) = h(t), and solve for t
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28.5t +1 = -4.9t^2 +32t +2
:
-4.9t +3.5t +1 = 0
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use quadratic formula to solve for t
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t = (-3.5 +square root((3.5)^2 -4 * (-4.9) * 1 ))/(2*(-4.9)) = -0.2187
:
t = (-3.5 -square root((3.5)^2 -4 * (-4.9) * 1 ))/(2*(-4.9)) = 0.933
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We ignore the negative value for t
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a) h(t) = -4.9t^2 +32t +2
:
h(0.933) = -4.9 * (0.933)^2 + 32 * (0.933) + 2 = 27.5906 
:
The skeet will be 27.5906 metres above the ground when it is hit
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b) The skeet will be hit after 0.933 seconds by the pellet
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