Question 1137636
.


            Although the post does not decipher all notations,  I interpret it in this way :


<pre>
        How many are there permutations of 5 elements that place the element "2" into position "5" ?
</pre>


The answer is 4! = 4*3*2*1 = 24.


You are free to make all possible permutations of remaining 4 elements in remained 4 positions.



Answered and solved.