Question 1137608
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<pre>
The probability is  {{{1/6}}}  to get the number "2" at the first rolling.

The probability is  {{{1/6}}}  to get the number "3" at the second rolling.

The probability is  {{{1/6}}}  to get the number "4" at the third rolling.

    .  .  .   and  so  on   .  .  .


As a result, the probability is  {{{(1/6)^6}}}  = {{{1/6^6}}}  to get this particular ordered set.
</pre>

Solved.