Question 103690
6x-4y=12

Graph the line intercepts and the third point?
To find the intercepts, just make one of the variables equal 0;
first put the equation in slope-intercept form;
-4y=-6x+12
{{{y=(-6/-4)x+12/-4}}}
{{{y=(6/4)x-3}}}
Find x-intercept;
{{{0=(6/4)x-3}}}
{{{3=(6/4)x}}}
{{{(4/6)3=x}}}
2=x - x-intercept
y=-3 - y-intercept
graph;
{{{graph (300,200, -5,5,-5,5 ,(6/4)x-3)}}}
:)