Question 1137518

A boy is two years younger than his sister. Three years ago, the sum of their ages was 48. What is the boy's age?
<pre>Let boy's age be B
Then sister's age is B + 2
Since their ages summed to 48, 3 years ago, their ages sum to 48 + 6, or 54, now
We then get: B + B + 2 = 54
2B = 52
Boy's age, or {{{highlight_green(matrix(1,5, B, "=", 52/2, "=", 26))}}}