Question 1137546
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A quadratic function has these characteristics:
x = 1 is the equation for the axis of symmetry.
x = - 1 is an x-intercept.
y = - 4 is the minimum value.
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Vertex has x coordinate 1, same as axis of symmetry.
y minimum at -4 means vertex is (1, -4).  This given as MINIMUM value of parabola, so equation can be of the form:


{{{y=a(x-1)^2-4}}}.


x intercept  -1 and vertex  (1, -4)  mean that the other x intercept is  1+2=3;  or  

{{{y=a(x+1)(x-3)}}}.


Those two formulas for y must be equal.
{{{a(x-1)^2-4=a(x+1)(x-3)}}}
Solve this for a.

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Let x be 0 in either equation and find y, for y-intercept.