Question 1137536
let the original fraction be {{{n/d}}}
:
A numerator is 3 less than the denominator.
n = d-3
 If each is increased by one, the new fraction is 10/11.
{{{((n+1))/((d+1))}}} = {{{10/11}}}
cross multiply
11(n+1) = 10(d+1)
11n + 11 = 10d + 10
11n = 10d + 10 - 11
11n = 10d - 1
replace n with (d-3)
11(d-3) = 10d - 1
11d - 33 = 10d = 1
11d - 10d = -1 + 33
d = 32
find n
n = 32-3
n = 29
The original fraction {{{29/32}}}

:
:
Check, adding 1 to n & d = 30/33 which reduces to 10/11