Question 1137541
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<pre>

Let x = # of adult tickets, y = # of child tickets.


From the condition, you have these 2 equations


         x +      y = 134        (1)    (counting tickets)

    9.80*x + 6.20*y = 1122.40    (2)    (counting money)


From equation (1), express  y = 134 - x  and substitute it into equation (2), You will get


    9.80x + 6.20*(134-x) = 1122.40.


Express x and calculate answer


    x = {{{(1122.40 - 6.20*134)/(9.80 - 6.20)}}} = 81.


Then from equation (1),  y = 134 - 81 = 53.


<U>ANSWER</U>.  81 adult tickets and 53 child tickets.


<U>CHECK</U>.   81*9.80 + 53*6.20 = 1122.40 dollars.   ! Correct !
</pre>

The problem solved using 2-equation setup and the Substitution method.


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It is a standard and typical ticket problem.


For ticket problems, &nbsp;read the lessons

&nbsp;&nbsp;&nbsp;&nbsp;- <A HREF=https://www.algebra.com/algebra/homework/coordinate/lessons/Using-systems-of-equations-to-solve-problems-on-Tickets.lesson>Using systems of equations to solve problems on tickets</A> 

&nbsp;&nbsp;&nbsp;&nbsp;- <A HREF=https://www.algebra.com/algebra/homework/coordinate/lessons/Three-methods-for-solving-standard-typical-problem-on-tickets.lesson>Three methods for solving standard (typical) problems on tickets</A>

in this site.


From these lessons, &nbsp;learn on how to solve such problems once and for all.


Also, &nbsp;you have this free of charge online textbook in ALGEBRA-I in this site

&nbsp;&nbsp;&nbsp;&nbsp;- <A HREF=https://www.algebra.com/algebra/homework/quadratic/lessons/ALGEBRA-I-YOUR-ONLINE-TEXTBOOK.lesson>ALGEBRA-I - YOUR ONLINE TEXTBOOK</A>.


The referred lessons are the part of this online textbook under the topic "<U>Systems of two linear equations in two unknowns</U>".