Question 1137499
<pre>
First ask, what is  {{{(3x^4)/x}}}?
That is {{{3x^3}}}.   After that you do what you normally do in long division...


          3x^3
      _________________________________________
x+1   |   3x^4   0x^3    -4x^2   4x     8
      |
      |



          3x^3   -3x^2    -x     5
      _________________________________________
x+1   |   3x^4   0x^3    -4x^2   4x     8
      |
      |   3x^4   3x^3
      ---------------
           0    -3x^3   -4x^2
                -3x^3   -3x^2
               --------------
                 0      -x^2   4x
                        -x^2  -x
                       ----------
                              5x      8
                              5x      5
                             -----------
                                      3

</pre>
{{{highlight(3x^3-3x^2-x+5+3/(x+1))}}}