Question 103716
: (-4xto the second y)2
__________
-12xy (to the -4)
:
Write it:
{{{((-4x^2y)^2)/((-12xy^(-4)))}}}
:
Square the numerator
{{{(16x^4y^2)/((-12xy^(-4)))}}}
:
{{{(16x^(4-1)y^(2+4))/(-12)}}}; combine x & y on the numerator
:
{{{(16x^3y^6)/(-12)}}}
:
{{{-(4x^3y^6)/3}}} is the answer
:
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