Question 1137426


Area of original rectangle is 

{{{12x^2+11x-5}}}....factor completely to find expressions for length and width

{{{12x^2-3x+15x-5}}}

{{{(12x^2-4x)+(15x-5)}}}

{{{4x(3x-1)+5(x-1)}}}

{{{(3x - 1) (4 x + 5)}}}

let
{{{(3x - 1)}}}=> be the length
{{{(4 x + 5)}}}=> be the width


 Area is changed by:
 
{{{decreasing}}} the length by {{{2}}} ft =>{{{(3x - 1-2)}}}=>{{{(3x - 3)}}}

and {{{increasing}}} the width by {{{4}}} ft=>{{{(4 x + 5+4)}}}=>{{{(4 x + 9)}}}

 the new area is:

{{{(3x - 3)(4 x + 9)}}}.....expand

{{{12 x^2 + 15 x - 27}}}