Question 1137323
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<pre>
x = 4*cos(t),

y = 4*sin(t) 


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{{{x^2}}} + {{{y^2}}} = {{{16*cos^2(t)}}} + {{{16*sin^2(t)}}} =  {{{16*(cos^2(t) + sin^2(t))}}} = 16.


Thus you get the equation


{{{x^2}}} + {{{y^2}}} = 16.


It is the equation of the circle of the radius 4 centered at the origin of the coordinate system in (x,y)-coordinate plane.
</pre>

Completed and solved.


The result of the elimination is an equation of the circle.