Question 1137288
For a fair die, the Probability(P) of rolling a number is 1/6
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P (rolling 1 or 2) = 1/6 + 1/6 = 2/6 = 1/3
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P (rolling a 3) = 1/6
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P (rolling 4 or 5 or 6) = 3/6 = 1/2
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Expected value on 1 roll of die is 700(1/3) +400(1/6) -600(1/2) = 0
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Expected value is linear so if you roll the die 10 times, expected value is 0 * 10 = 0
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Answer is B
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