Question 1137264
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<pre>
Let x = amount invested at 12%, in dollars.

Then the second amount, which suffered  the 5% loss,  is the rest (21020-x) dollars.



The interest from the 12% interest amount is 0.12*x  dollars.

The 5% loss from the second   amount is 0.05*(21020-x)   dollars.



Your equation is


    <U>interest</U> - <U>loss</U>           = <U>final interest</U>,   or


    0.12*x   - 0.05*(21020-x) = 2026   dollars.


From the equation, express x and calculate the answer


    x = {{{(2026 + 0.05*21020)/(0.12+0.05)}}} = 18100.


<U>Answer</U>.  The amount at 12% is $18100;  the rest  $21020-$18100 = $2920 is the amount suffered 5% loss.


<U>Check</U>.   0.12*18100 - 0.05*2920 = 2026 dollars.   ! Correct !
</pre>

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It is a typical and standard problem on investment.


To see many other similar solved problems on investment, &nbsp;look into the lesson

&nbsp;&nbsp;&nbsp;&nbsp;- <A HREF=https://www.algebra.com/algebra/homework/coordinate/lessons/Using-systems-of-equations-to-solve-problems-on-investment.lesson>Using systems of equations to solve problems on investment</A>

in this site.


You will find there different approaches &nbsp;(using one equation or a system of two equations in two unknowns), &nbsp;as well as 
different methods of solution to the equations &nbsp;(Substitution, &nbsp;Elimination).


Also, &nbsp;you have this free of charge online textbook in ALGEBRA-I in this site

&nbsp;&nbsp;&nbsp;&nbsp;- <A HREF=https://www.algebra.com/algebra/homework/quadratic/lessons/ALGEBRA-I-YOUR-ONLINE-TEXTBOOK.lesson>ALGEBRA-I - YOUR ONLINE TEXTBOOK</A>.


The referred lesson is the part of this online textbook under the topic &nbsp;"<U>Systems of two linear equations in two unknowns</U>".



Save the link to this online textbook together with its description


Free of charge online textbook in ALGEBRA-I
https://www.algebra.com/algebra/homework/quadratic/lessons/ALGEBRA-I-YOUR-ONLINE-TEXTBOOK.lesson


to your archive and use it when it is needed.