Question 1137252
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<pre>
In order for three segments of the length a, b and c form a triangle, three "triangle inequalities" must be satisfied


    a + b > c,

    a + c > b,

    b + c > a.


In wording form, it means that the sum of any two side lengths must be greater than the length of the third side.


In our case, 

    19 + 10 = 29,


but inequality 

    19 + 10 > 29

is not held.


Therefore, the given three segments do not form a triangle.
</pre>


Answered, explained and completed.



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I wrote my post because the post by &nbsp;@josgarithmetic does not explain the subject correctly and only can mislead a young inexperienced student.


My advise to any reader who will see my post, &nbsp;is to ignore writing by &nbsp;@josgarithmetic, &nbsp;since it may harm your mind.


I'd called it &nbsp;"one more fake solution from &nbsp;@josgarithmetic", &nbsp;but it would be too soft / (gentle) name for it . . . 



"RUBBISH" &nbsp;is a correct name.



/\/\/\/\/\/\/


It is paradoxically, but @josgarithmetic, &nbsp;being a totally unqualified as a tutor and producing tons and thousands 

fake solutions, &nbsp;collects enthusiastic feedback from the visitors, &nbsp;much more than any other tutor in this forum.


I thought long time about it, &nbsp;and came to the conclusion, &nbsp;that it tells a lot about the visitors.