Question 103836
Let S = Sarah's present age and D = Denise's present age.
From the problem description, you can write:
1) {{{highlight(S = 3D+6)}}}  "Sarah is 6 years more than 3 times as old as Denise"
2) {{{(highlight(S)+14) + (D+14) = 82}}} "In 14 years, the sum of their ages will be 82"
Substitute the S from equation 1) into equation 2) and solve for D.
2a) {{{(highlight(3D+6)+14) + (D+14) = 82}}}  Simplify.
{{{4D+34 = 82}}} Subtract 34 from both sides.
{{{4D = 48}}} Divide by both sides by 4.
{{{D = 12}}} This is Denise's present age.
{{{S = 3D+6}}}
{{{S = 3(12)+6}}}
{{{S = 36+6}}}
{{{S = 42}}} This is Sarah's present age.