Question 1137162

{{{R=log(A)+B}}}

{{{4.1=log(A[2])+B}}}

{{{3.2=log(A[1])+B}}}

{{{log(A[2])+B-log(A[1])-B=4.1-3.2}}}

{{{log(A[2])-log(A[1])=0.9}}}

{{{log(A[2]/A[1])=0.9}}}

{{{A[2]/A[1]=10^0.9}}}

{{{A[2]/A[1]=7.94328}}}=>{{{7.94328}}} times more intense