Question 1137126
{{{g(-2)=2(-2)^3+3(-2)^2-3(-2)+4}}}
{{{g(-2)=2(-8)+3(4)-3(-2)+4}}}
{{{g(-2)=(-16)+(12)+(6)+4}}}
{{{g(-2)=6}}}
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{{{g(-1)=2(-1)^3+3(-1)^2-3(-1)+4}}}
{{{g(-1)=2(-1)+3(1)-3(-1)+4}}}
{{{g(-1)=(-2)+(3)+(3)+4}}}
{{{g(-1)=8}}}
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Since there is no change in sign, the intermediate value theorem can't be used to determine if there a zero in the interval [-2,-1]