Question 1137100

zeroes:

{{{ -sqr(6)}}}, => you also have {{{ sqr(6)}}}
{{{3}}}


{{{f(x)=(x-x[1])(x-x[2])(x-x[3])}}}

{{{f(x)=(x-(-sqrt(6)))(x-sqr(6))(x-3)}}}

{{{f(x)=(x+sqrt(6))(x-sqr(6))(x-3)}}}

{{{f(x)=(x^2-(sqr(6))^2)(x-3)}}}

{{{f(x)=(x^2-6)(x-3)}}}

{{{f(x)=x^3 - 3 x^2 - 6 x + 18}}}