Question 1137068
{{{log(10, 3z)=2}}}

{{{log(10, 3)+log(10,z)=2}}}

{{{log(10,z)=2-log(10, 3)}}}....since {{{log(10,100)=2}}}, we have

{{{log(10,z)=log(10,100)-log(10, 3)}}} 

{{{log(10,z)=log(10,100/3)}}} .....since log same

{{{z=100/3}}}