Question 1137022
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P(at least 7 boys) = P(7 boys or 8 boys) = P(7 boys) + P(8 boys)<br>
P(8 boys) = (8C8)(1/2)^8 = 1/256
P(7 boys) = (8C7)(1/2)^8 = 8/256<br>
P(at least 7 boys) = 9/256