Question 103817
{{{9/(x-5 )-1 = 8/(x+5)}}}  simplifies to {{{9/(x-5)-8/(x+5)-1=0}}}


The least common denominator is {{{(x-5)(x+5)}}}
{{{9(x+5)/(x-5)(x+5) -  8(x-5)/(x-5)(x+5)- 1(x-5)(x+5)/ (x-5)(x+5) = 0}}}

{{{(9(x+5) - 8(x-5) - 1(x-5)(x+5))/(x-5)(x+5) = 0}}} now both sides multiply by {{{(x-5)(x+5)}}} and you will have

{{{(9(x+5) - 8(x-5) - 1(x-5)(x+5))/(x-5)(x+5) = 0}}} /* {{{(x-5)(x+5)}}} 

this will eliminate denominator, and you will have

{{{(9(x+5) - 8(x-5) - 1(x-5)(x+5)) = 0}}} 

{{{9x + 45 - 8x + 40 - (x^2+ 5x -5x -25) = 0}}} 

{{{x + 85 - x^2 + 25 = 0}}} 

{{{- x^2 + x + 110 = 0}}} 


now you can use quadratic formula to find {{{x1}}} and {{{x2}}}, then you can graf it


*[invoke quadratic_formula -1, 1, 110, "x"]