Question 1136955


given:

the line passing through the point ({{{-6}}}, {{{-3}}}) 
having a slope of {{{m=-1/3}}} 

use point slope formula

{{{y-y[1]=m(x-x[1])}}}

{{{y-(-3)=-(1/3)(x-(-6))}}}

{{{y+3=-(1/3)(x+6)}}}

{{{y+3=-(1/3)x-2}}}

{{{y=-(1/3)x-2-3}}}

{{{y=-(1/3)x-5}}}


{{{drawing ( 600, 600, -10, 10, -10, 10,
circle(-6,-3,.12),locate(-6,-3,p(-6,-3)),
graph( 600, 600, -10, 10, -10, 10, -(1/3)x-5)) }}}