Question 1136890
Find an nth degree polynomial function with real coefficients such that:

n=3
1 and i are zeros
f(-1)=8
----------
Zeroes are 1, i & -i
--> (x-1)*(x^2 + 1) = x^3 - x^2 + x - 1
---------
f(-1) = -1 - 1 - 1 - 1 = -4
Multiply by -2
--> f(x) -2x^3 + 2x^2 - 2x + 2
============
f(-1) = 2 + 2 + 2 + 2 = 8