Question 1136785
(x + 3)^(1/3) = (x - 1)^(1/2), find the value of x. 
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Raise to the 6th power:
(x + 3)^2 = (x - 1)^3
x^2 + 6x + 9 = x^3 - 3x^2 + 3x - 1
x^3 - 4x^2 - 3x - 10 = 0
x = 5
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x^2 + x + 2 = 0
{{{x = -1/2 + i*sqrt(7)/2}}}
{{{x = -1/2 - i*sqrt(7)/2}}}