Question 1136777
Notice the numerator and denominator each have factor of c, so  c/c=1.

<pre>
            c^3     2c^2      -4c        0
      __________________________________________________
9c    |    9c^4     18c^3    -36c^2      0c     -81
      |
      |    9c^4
         -------
           0        18c^3
                    18c^3
                  --------
                     0       -36c^2
                             -36c^2
                            --------
                              0         0c
                                        0c
                                      -----
                                        0      -81  remainder
</pre>
{{{c^3+2c^2-4c-81/(9c)=highlight(c^3+2c^2-4c-9/c)}}}