Question 1136722
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y=ax^2 has a vertical axis of symmetry; a horizontal axis of symmetry with vertex at the origin means the equation is x = ay^2.<br>
Find the value of a by substituting the coordinates of the given point in the equation.<br>
{{{-2 = a(5^2)}}}
{{{-2 = 25a}}}
{{{a = -2/25}}}<br>
The equation is<br>
{{{x = (-2/25)y^2}}}<br>
A graph, showing the parabola passing through (-2,5)...<br>
{{{graph(400,400,-10,2,-15,15,sqrt((-25/2)x),-sqrt((-25/2)x))}}}