Question 103787
To factor this, simply use the difference of squares


{{{a^2-b^2=(a+b)(a-b)}}}



So let a=x^2 (it is the square root of {{{x^4}}}) and b=36 (it is the square root of 1296) to get



{{{(x^2)^2-(36)^2=(x^2+36)(x^2-36)}}}



Now factor {{{x^2-36}}} to {{{(x+6)(x-6)}}}. Again use the difference of squares to factor



So {{{x^4 - 1296}}} factors to {{{(x^2+36)(x+6)(x-6)}}}