Question 1136671
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<pre>
Let x be daily fee and y be additional charge per mile.

Then from the condition we have this system of 2 equations in 2 unknowns



    4x + 390y = 260.50  dollars    (1)

    3x + 190y = 159.50  dollars    (2)



Now I apply the determinant method (the Cramer's rule) :


    1)  d = determinant of the coefficient matrix = 4*190 - 3*390 = -410;


    2)  x = {{{(260.50*190 - 159.50*390)/(-410)}}} = 31;


    3)  y = {{{(4*159.50 - 3*260.50)/(-410)}}} = 0.35.


<U>ANSWER</U>.  Daily fee is $31;  Mileage charge is $0.35 per mile.
</pre>

Solved.


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On the Determinants' method for solving the systems of two linear equations in two unknowns see the lessons 

&nbsp;&nbsp;&nbsp;&nbsp;- <A HREF =http://www.algebra.com/algebra/homework/coordinate/lessons/Solution-of-the-lin-syst-of-two-eqns-with-two-unknowns-using-det.lesson>Solution of the linear system of two equations in two unknowns using determinant</A> 

in this site.


Also, &nbsp;you have this free of charge online textbook in ALGEBRA-I in this site

&nbsp;&nbsp;&nbsp;&nbsp;- <A HREF=https://www.algebra.com/algebra/homework/quadratic/lessons/ALGEBRA-I-YOUR-ONLINE-TEXTBOOK.lesson>ALGEBRA-I - YOUR ONLINE TEXTBOOK</A>.


The referred lesson is the part of this online textbook under the topic "<U>Systems of two linear equations in two unknowns</U>".



Save the link to this online textbook together with its description


Free of charge online textbook in ALGEBRA-I
https://www.algebra.com/algebra/homework/quadratic/lessons/ALGEBRA-I-YOUR-ONLINE-TEXTBOOK.lesson


to your archive and use it when it is needed.