Question 1136602
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Integral of f(x) over the segment [-1,1] must be equal to 1.


Integral of f(x) over the segment [-1,1]  is  {{{k*((1/3) - (-1/3))}}} = {{{(2*k)/3}}}.


So, the equation to determine k is


    {{{(2k)/3}}} = 1

    2k = 3

    k = {{{3/2}}}.    <U>ANSWER</U>
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