Question 1136587
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<pre>
The shortest and most straightforward way to solve this problem is to use the proportion


    {{{sector_area/circle_area}}} = {{{central_angle/(2*pi)}}},   or


    {{{((17pi/2))/circle_area}}} = {{{((17pi/9))/(2*pi)}}}.


Or, canceling common factors 17, {{{pi}}} and 2 in both sides


    {{{1/circle_area}}} = {{{1/(9*pi)}}},   


which implies


    Circle area = {{{9*pi}}}.     <U>ANSWER</U>
</pre>

Solved.