Question 1136557
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Let N be the number of nickels.


Then the number of quarters is 2N, according to the condition,
and the number of dimes is the rest (88 - N - 2N) = 88-3N.


The "money" equation then is


    5N + 10*(88-3N) + 25*(2N) = 1455 cents.


Simplify and solve for N


    5N + 880 - 30N + 50N = 1455

    25N = 1455 - 880

    25N = 575  =============>  N = {{{575/25}}} = 23.


<U>ANSWER</U>.  23 nickels,  2*23 = 46 quarters and  88-23-46 = 19 dimes.


<U>CHECK</U>.   23*5 + 46*25 + 19*10 = 1455 cents.    ! Correct !
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Solved.


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The lesson to learn from my post is <U>THIS</U> :


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    This problem is to be solved by reduction to one single equation in one unknown.
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