Question 1136533
let w be the width, and l be the length
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l = w+20
:
(w+20) *w = Area(A)
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1) w^2 +20w = A
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(w+20-5) *(w+4) = A
:
(w+15) *(w+4) = A
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2) w^2 +19w +60 = A
:
the areas are the same, so set equation 1 equal to equation 2
:
w^2 +20w = w^2 +19w +60
:
w = 60
:
l = 60 +20 = 80
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The dimensions of the original field are length = 80 yards and width = 60 yards
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check the answer
:
80 * 60 = 4800 square yards
:
75 * 64 = 4800 square yards
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answer checks
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