Question 103749
{{{f[x]=a(x-h)^2+k}}} Standard form of the quadratic equation {{{x<>0}}}
The vertex point is (h,k).
h=2 k=4
f[x]=a(x-2)^2+4
=x^2-4x+4+4 (let a=1)
=x^2-4x+8
So, b=-4 and c=8
Ed
{{{graph(500,500,-10,10,-10,10,x^2-4x+8)}}}