Question 1136378
A 99% CI interval is mean +/- z(0.995)sqrt (p*(1-p)/n); z=2.576
p=1410/3161=0.4461
the half-interval is 2.576*sqrt (.4461*0.5539/3161)=0.0228
the interval is (0.4233, 0.4689)

We don't know the true proportion but we are extremely confident it lies in this interval.This is C.  CIs are about populations, not samples when they are interpreted.  That is why they are constructed.