Question 1136384

({{{h}}}, {{{k}}}) = ({{{-3}}}, {{{-1}}}), ({{{x}}},{{{ y}}}) = ({{{-5}}}, {{{3}}})

{{{y=a(x-h)^2+k}}}...given {{{h=-3}}},{{{k=-1}}}.{{{x=-5}}},{{{y=3}}}; plug it all in and calculate {{{a}}}

{{{3=a(-5-(-3))^2+(-1)}}}

{{{3=a(-5+3)^2-1}}}

{{{3+1=a(-2)^2}}}

{{{4=a*4}}}

{{{a=1}}}

your equation is: {{{y=(x+3)^2-1}}}


 {{{drawing ( 600, 600, -10, 10, -10, 10, 
circle(-3,-1,.12),locate(-3,-1,V(-3,-1)), 
circle(-5,3,.12),locate(-5,3,p(-5,3)),
graph( 600, 600, -10, 10, -10, 10, (x+3)^2-1)) }}}