Question 1136341


supplementary angles are two angles whose sum is {{{180}}}°

let one angle be {{{alpha}}} and its supplement {{{beta}}}

so, {{{alpha+beta=180}}}° ........eq.1

if measure of {{{alpha}}}  is {{{60}}}°  more than {{{triple}}} that of its supplement {{{beta}}}, we have

{{{alpha=3beta+60}}}°........substitute in eq.1

{{{3beta+60+beta=180}}}° .........solve for {{{beta}}}

{{{4beta=180-60}}}° 

{{{4beta=120}}}° 

{{{beta=120/4}}}° 

{{{beta=30}}}° 


find {{{alpha}}}


{{{alpha=3beta+60}}}°

{{{alpha=3*30+60}}}°

{{{alpha=150}}}°