Question 1136257
ASA launches a rocker at T=0 seconds. It's height, in meters above sea level, as a function of time is given by H(T)=-4.9T^2 + 229T +185. 

Assuming that the rocket will splash down into the ocean, at what time does splashdown occur? 
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it's = it is.
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I would solve the problem, but these entries irritate me.
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The rocket splashes down after ___ seconds
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How high above sea-level does the rocket get at its peak? 
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The rocket peaks at ___ meters above sea-level
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this is not useful.
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H(T)=-4.9T^2 + 229T +185
At impact, h(t) = 0
-4.9T^2 + 229T +185 = 0
Solve for t
*[invoke solve_quadratic_equation -4.9,229,185]
Ignore the negative value.
t = ~ 47.529 seconds
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The peak (max height) is the vertex of the parabola, at t = -b/2a
t = -229/-9.8 = ~ 23.367 seconds
h(23.367) =~ 2675.5 meters
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PS - this is not a rocket, it's a projectile.
Rockets accelerate upward.