Question 1136200

{{{n=3}}}; 
{{{1}}} and {{{3i}}} are zeros 

complex zeros always come in pairs, so you also have {{{-3i}}}

use zero product formula:

{{{f(x)=(x-x[1])(x-x[2])(x-x[3])}}}...plug in given zeros

{{{f(x)=(x-1)(x-3i)(x-(-3i))}}}

{{{f(x)=(x-1)(x-3i)(x+3i)}}}

{{{f(x)=(x-1)(x^2-(3i)^2)}}}

{{{f(x)=(x-1)(x^2-(3^2* i^2))}}}.......{{{i^2=-1)}}}

{{{f(x)=(x-1)(x^2-(9*-1))}}}

{{{f(x)=(x-1)(x^2+9)}}}

{{{f(x)=x^3-x^2+9x-9}}}