Question 1136176
.


The condition missed the following:


<pre>
    1.  Did they start from one common point ?

    2.  Did they start simultaneously ?

    3.  Do they move in the same or opposite directions ?
</pre>

For introductory lessons on Travel & Distance see the lessons

&nbsp;&nbsp;&nbsp;&nbsp;- <A HREF=http://www.algebra.com/algebra/homework/word/travel/Travel-and-Distance-problems.lesson>Travel and Distance problems</A>  

&nbsp;&nbsp;&nbsp;&nbsp;- <A HREF=https://www.algebra.com/algebra/homework/word/travel/Travel-and-Distance-problems-for-two-bodies-moving-toward-each-other.lesson>Travel and Distance problems for two bodies moving in opposite directions</A> 

&nbsp;&nbsp;&nbsp;&nbsp;- <A HREF=https://www.algebra.com/algebra/homework/word/travel/Typical-catching-up-Travel-and-Distance-problems.lesson>Travel and Distance problems for two bodies moving in the same direction (catching up)</A>

in this site.


They are written specially for you.


Learn from there on how to formulate these problems.



Happy learning !



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Comment from student: Yes they start the same time and travel in the same direction 
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<U>My response</U> :  &nbsp;&nbsp;OK.


Then the solution can be implemented in two lines :


<pre>
    The separation rate is then  (10-4) = 6 miles per hour.

    Hence, they will be 24 miles apart in  {{{24/6}}} = 4 hours.    <U>ANSWER</U>
</pre>


Or the <U>formal Algebra solution</U> :


<pre>
Let "t" be the time when they be 24 miles apart.


At that time Kevin will cover the distance of  10*t  miles, while Stanley will cover 4*t miles.


The distance difference should be 24 miles; it gives you an equation


    10t - 4t = 24  miles,

    6t       = 24 miles

     t       = {{{24/6}}} = 4 hours.     <U>ANSWER</U>
</pre>

Thus I showed you two ways the problem can be solved.